determine a Filter’s GeometryRepresentation-ID
The only way I see is to use the python shell.
GetRepresentations()
gives you a dict of {(name, id): representation}GetRepresentation()
gives you the representation object for the active object in the active view.
Then with a reverse search you can find the correct name.
start with a cloned/linked view
I think you can create a python script that:
- create a second view
- Show filters in second view depending on the first view
- create Property links accordingly
For first and second point, the python trace can help you.
For the property links, this test from ParaView source may be helpful.